(x+2)(x^2-7x+4)=0

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Solution for (x+2)(x^2-7x+4)=0 equation: 


Simplifying
(x + 2)(x2 + -7x + 4) = 0

Reorder the terms:
(2 + x)(x2 + -7x + 4) = 0

Reorder the terms:
(2 + x)(4 + -7x + x2) = 0

Multiply (2 + x) * (4 + -7x + x2)
(2(4 + -7x + x2) + x(4 + -7x + x2)) = 0
((4 * 2 + -7x * 2 + x2 * 2) + x(4 + -7x + x2)) = 0
((8 + -14x + 2x2) + x(4 + -7x + x2)) = 0
(8 + -14x + 2x2 + (4 * x + -7x * x + x2 * x)) = 0
(8 + -14x + 2x2 + (4x + -7x2 + x3)) = 0

Reorder the terms:
(8 + -14x + 4x + 2x2 + -7x2 + x3) = 0

Combine like terms: -14x + 4x = -10x
(8 + -10x + 2x2 + -7x2 + x3) = 0

Combine like terms: 2x2 + -7x2 = -5x2
(8 + -10x + -5x2 + x3) = 0

Solving
8 + -10x + -5x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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